How to solve 48-89+(8x8)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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Question

$$48-89+(8x8)$$

Differentiate w.r.t. x_8

$8$

Steps Using Derivative Rule for Sum

Subtract $89$ from $48$ to get $-41$.

$$\frac{\mathrm{d}}{\mathrm{d}x_{8}}(-41+8x_{8})$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$8x_{8}^{1-1}$$

Subtract $1$ from $1$.

$$8x_{8}^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$8\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$8$$

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Evaluate

$8x_{8}-41$

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Example

Question

Differentiate w.r.t. x_8

Steps Using Derivative Rule for Sum

Evaluate

Solution Steps