$$49 a ^ { 2 } - 2 a b + \frac { b ^ { 2 } } { 49 } 4 x ^ { 2 } + 2$$
$\frac{4b^{2}x^{2}-98ab+2401a^{2}+98}{49}$
$$\frac{2401a^{2}-98ab+4b^{2}x^{2}+98}{49}$$
Show Solution
Hide Solution
$\frac{4\left(bx\right)^{2}}{49}-2ab+49a^{2}+2$