How to solve 49/9-1/9

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 49/9-1/9 | Equatix

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$$49/9-1/9$$

$\frac{16}{3}\approx 5.333333333$

Since $\frac{49}{9}$ and $\frac{1}{9}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{49-1}{9}$$

Subtract $1$ from $49$ to get $48$.

$$\frac{48}{9}$$

Reduce the fraction $\frac{48}{9}$ to lowest terms by extracting and canceling out $3$.

$$\frac{16}{3}$$

$\frac{2 ^ {4}}{3} = 5\frac{1}{3} = 5.333333333333333$