Solve 49+(x)^(2)+14x=17+17x+1+(x)^(2) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$49+ { x }^{ 2 } +14x=17+17x+1+ { x }^{ 2 }$$

Solve for x

$x = \frac{31}{3} = 10\frac{1}{3} \approx 10.333333333$

Steps for Solving Linear Equation

Add $17$ and $1$ to get $18$.

$$49+x^{2}+14x=18+17x+x^{2}$$

Subtract $17x$ from both sides.

$$49+x^{2}+14x-17x=18+x^{2}$$

Combine $14x$ and $-17x$ to get $-3x$.

$$49+x^{2}-3x=18+x^{2}$$

Subtract $x^{2}$ from both sides.

$$49+x^{2}-3x-x^{2}=18$$

Combine $x^{2}$ and $-x^{2}$ to get $0$.

$$49-3x=18$$

Subtract $49$ from both sides.

$$-3x=18-49$$

Subtract $49$ from $18$ to get $-31$.

$$-3x=-31$$

Divide both sides by $-3$.

$$x=\frac{-31}{-3}$$

Fraction $\frac{-31}{-3}$ can be simplified to $\frac{31}{3}$ by removing the negative sign from both the numerator and the denominator.

$$x=\frac{31}{3}$$