Use Negative Power Rule: \({x}^{-a}=\frac{1}{{x}^{a}}\).
\[\begin{aligned}&49\times {2}^{-3}\\&{7}^{3}\times 10\times \frac{1}{{2}^{5}}\end{aligned}\]
Simplify \({2}^{5}\) to \(32\).
\[\begin{aligned}&49\times {2}^{-3}\\&{7}^{3}\times 10\times \frac{1}{32}\end{aligned}\]
49*2^-3;7^3*10*1/32
