How to solve 49 imes329

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 49\times329 | Equatix

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Question

$$49 \times 329$$

Evaluate

$16121$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}49\\\underline{\times\phantom{99}329}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 49 with 9. Write the result 441 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}49\\\underline{\times\phantom{99}329}\\\phantom{\times99}441\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 49 with 2. Write the result 98 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}49\\\underline{\times\phantom{99}329}\\\phantom{\times99}441\\\phantom{\times99}98\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 49 with 3. Write the result 147 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}49\\\underline{\times\phantom{99}329}\\\phantom{\times99}441\\\phantom{\times99}98\phantom{9}\\\underline{\phantom{\times}147\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times999}49\\\underline{\times\phantom{99}329}\\\phantom{\times99}441\\\phantom{\times99}98\phantom{9}\\\underline{\phantom{\times}147\phantom{99}}\\\phantom{\times}16121\end{array}$$

Show Solution

Factor

$7^{3}\times 47$