How to solve 4a+2b+a-b-3a-b

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4a+2b+a-b-3a-b | Equatix

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$4a+2b+a-b-3a-b$$

Evaluate

$2a$

Solution Steps

Combine $4a$ and $a$ to get $5a$.

$$5a+2b-b-3a-b$$

Combine $2b$ and $-b$ to get $b$.

$$5a+b-3a-b$$

Combine $5a$ and $-3a$ to get $2a$.

$$2a+b-b$$

Combine $b$ and $-b$ to get $0$.

$$2a$$

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Differentiate w.r.t. a

$2$

Steps Using Definition of a Derivative

Combine $4a$ and $a$ to get $5a$.

$$\frac{\mathrm{d}}{\mathrm{d}a}(5a+2b-b-3a-b)$$

Combine $2b$ and $-b$ to get $b$.

$$\frac{\mathrm{d}}{\mathrm{d}a}(5a+b-3a-b)$$

Combine $5a$ and $-3a$ to get $2a$.

$$\frac{\mathrm{d}}{\mathrm{d}a}(2a+b-b)$$

Combine $b$ and $-b$ to get $0$.

$$\frac{\mathrm{d}}{\mathrm{d}a}(2a)$$

The derivative of $ax^{n}$ is $nax^{n-1}$.

$$2a^{1-1}$$

Subtract $1$ from $1$.

$$2a^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$2\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$2$$

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