How to solve 4a + 5 = 31

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4a + 5 = 31 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$4a+5=31$$

Solve for a

$a = \frac{13}{2} = 6\frac{1}{2} = 6.5$

Steps for Solving Linear Equation

Subtract $5$ from both sides.

$$4a=31-5$$

Subtract $5$ from $31$ to get $26$.

$$4a=26$$

Divide both sides by $4$.

$$a=\frac{26}{4}$$

Reduce the fraction $\frac{26}{4}$ to lowest terms by extracting and canceling out $2$.

$$a=\frac{13}{2}$$

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Question

Solve for a

Steps for Solving Linear Equation