How to solve 4a+7(3a-9)=58

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4a+7(3a-9)=58 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$4a+7(3a-9)=58$$

Solve for a

$a = \frac{121}{25} = 4\frac{21}{25} = 4.84$

Steps for Solving Linear Equation

Use the distributive property to multiply $7$ by $3a-9$.

$$4a+21a-63=58$$

Combine $4a$ and $21a$ to get $25a$.

$$25a-63=58$$

Add $63$ to both sides.

$$25a=58+63$$

Add $58$ and $63$ to get $121$.

$$25a=121$$

Divide both sides by $25$.

$$a=\frac{121}{25}$$

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Question

Solve for a

Steps for Solving Linear Equation