$$4a^{2}+6a-7; 4a^{2}+6$$
$\frac{4a^{2}+6a-7}{2\left(2a^{2}+3\right)}$
$$\frac{4\left(a-\left(-\frac{1}{4}\sqrt{37}-\frac{3}{4}\right)\right)\left(a-\left(\frac{1}{4}\sqrt{37}-\frac{3}{4}\right)\right)}{2\left(2a^{2}+3\right)}$$
$$\frac{2\left(a-\left(-\frac{1}{4}\sqrt{37}-\frac{3}{4}\right)\right)\left(a-\left(\frac{1}{4}\sqrt{37}-\frac{3}{4}\right)\right)}{2a^{2}+3}$$
$$\frac{2a^{2}+3a-\frac{7}{2}}{2a^{2}+3}$$
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