Question

$$4m^{2}+2m=-1; m^{2}+\frac{1}{16m^{2}}=?$$

Solve for m, n

$m=\frac{-\sqrt{3}i-1}{4}\approx -0.25-0.433012702i\text{, }n=-\frac{1}{4}=-0.25$
$m=\frac{-1+\sqrt{3}i}{4}\approx -0.25+0.433012702i\text{, }n=-\frac{1}{4}=-0.25$