Solve for \(L\) in \(4mH=18L/\).
Solve for \(L\).
\[4mH=18L/\]
Simplify \(18L/\) to \(18L\).
\[4mH=18L\]
Divide both sides by \(18\).
\[\frac{4mH}{18}=L\]
Simplify \(\frac{4mH}{18}\) to \(\frac{2mH}{9}\).
\[\frac{2mH}{9}=L\]
Switch sides.
\[L=\frac{2mH}{9}\]
\[L=\frac{2mH}{9}\]
Substitute \(L=\frac{2mH}{9}\) into \(8x+4=3(x-1)+7\).
Start with the original equation.
\[8x+4=3(x-1)+7\]
Let \(L=\frac{2mH}{9}\).
\[8x+4=3(x-1)+7\]
Simplify.
\[8x+4=3x+4\]
\[8x+4=3x+4\]
Solve for \(x\) in \(8x+4=3x+4\).
Solve for \(x\).
\[8x+4=3x+4\]
Cancel \(4\) on both sides.
\[8x=3x\]
Move all terms to one side.
\[8x-3x=0\]
Simplify \(8x-3x\) to \(5x\).
\[5x=0\]
Divide both sides by \(5\).
\[x=0\]
\[x=0\]
Therefore,
\[\begin{aligned}&L=\frac{2mH}{9}\\&x=0\end{aligned}\]
L=(2*mH)/9;x=0
