$$4n=2n\frac{-11}{6}$$
$n=0$
$$4n=2n\left(-\frac{11}{6}\right)$$
$$4n=\frac{2\left(-11\right)}{6}n$$
$$4n=\frac{-22}{6}n$$
$$4n=-\frac{11}{3}n$$
$$4n+\frac{11}{3}n=0$$
$$\frac{23}{3}n=0$$
$$n=0$$
Show Solution
Hide Solution