How to solve 4P ^ 2 - 4d ^ 2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4P ^ 2 - 4d ^ 2 | Equatix

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$4P^{2}-4d^{2}$$

Factor

$4\left(P-d\right)\left(P+d\right)$

Solution Steps

Factor out $4$.

$$4\left(P^{2}-d^{2}\right)$$

Consider $P^{2}-d^{2}$. The difference of squares can be factored using the rule: $a^{2}-b^{2}=\left(a-b\right)\left(a+b\right)$.

$$\left(P-d\right)\left(P+d\right)$$

Rewrite the complete factored expression.

$$4\left(P-d\right)\left(P+d\right)$$

Show Solution

Evaluate

$4\left(P^{2}-d^{2}\right)$

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Factor

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Evaluate