Solve 4x/9+1/3+13/108x=8x+19/18 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$4x/9+1/3+13/108x=8x+19/18$$

Solve for x

$x=-\frac{78}{803}\approx -0.097135741$

Steps for Solving Linear Equation

Multiply both sides of the equation by $108$, the least common multiple of $9,3,108,18$.

$$12\times 4x+36+13x=864x+114$$

Multiply $12$ and $4$ to get $48$.

$$48x+36+13x=864x+114$$

Combine $48x$ and $13x$ to get $61x$.

$$61x+36=864x+114$$

Subtract $864x$ from both sides.

$$61x+36-864x=114$$

Combine $61x$ and $-864x$ to get $-803x$.

$$-803x+36=114$$

Subtract $36$ from both sides.

$$-803x=114-36$$

Subtract $36$ from $114$ to get $78$.

$$-803x=78$$

Divide both sides by $-803$.

$$x=\frac{78}{-803}$$

Fraction $\frac{78}{-803}$ can be rewritten as $-\frac{78}{803}$ by extracting the negative sign.

$$x=-\frac{78}{803}$$