Solve 4x-{2x-1-[5-(3\times1)+2x+1]}=0 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$4x- \{ 2x-1-[5-(3 \times 1)+2x+1] \} =0$$

Solve for x

$x=-1$

Steps for Solving Linear Equation

Multiply $3$ and $1$ to get $3$.

$$4x-\left(2x-1-\left(5-3+2x+1\right)\right)=0$$

Subtract $3$ from $5$ to get $2$.

$$4x-\left(2x-1-\left(2+2x+1\right)\right)=0$$

Add $2$ and $1$ to get $3$.

$$4x-\left(2x-1-\left(3+2x\right)\right)=0$$

To find the opposite of $3+2x$, find the opposite of each term.

$$4x-\left(2x-1-3-2x\right)=0$$

Subtract $3$ from $-1$ to get $-4$.

$$4x-\left(2x-4-2x\right)=0$$

Combine $2x$ and $-2x$ to get $0$.

$$4x-\left(-4\right)=0$$

The opposite of $-4$ is $4$.

$$4x+4=0$$

Subtract $4$ from both sides. Anything subtracted from zero gives its negation.

$$4x=-4$$

Divide both sides by $4$.

$$x=\frac{-4}{4}$$

Divide $-4$ by $4$ to get $-1$.

$$x=-1$$