How to solve 4x - 2 > x + 3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4x - 2 > x + 3 | Equatix

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3(r+2s)=2t-4

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Question

$$4x-2>x+3$$

Solve for x

$x>\frac{5}{3}$

Solution Steps

Subtract $x$ from both sides.

$$4x-2-x>3$$

Combine $4x$ and $-x$ to get $3x$.

$$3x-2>3$$

Add $2$ to both sides.

$$3x>3+2$$

Add $3$ and $2$ to get $5$.

$$3x>5$$

Divide both sides by $3$. Since $3$ is positive, the inequality direction remains the same.

$$x>\frac{5}{3}$$

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Solve for x

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