Question

$$4x-3=\overline{5}x+1$$

Answer

$$o=(4*(x-1))/(5*e^2*IM*v*r*l*n*x)$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[4x-3=ov{e}^{2}rl\imath n\times 5x+1\]
Regroup terms.
\[4x-3=5{e}^{2}\imath ovrlnx+1\]
Regroup terms.
\[4x-3=1+5{e}^{2}\imath ovrlnx\]
Subtract \(1\) from both sides.
\[4x-3-1=5{e}^{2}\imath ovrlnx\]
Simplify  \(4x-3-1\)  to  \(4x-4\).
\[4x-4=5{e}^{2}\imath ovrlnx\]
Divide both sides by \(5\).
\[\frac{4x-4}{5}={e}^{2}\imath ovrlnx\]
Factor out the common term \(4\).
\[\frac{4(x-1)}{5}={e}^{2}\imath ovrlnx\]
Divide both sides by \({e}^{2}\).
\[\frac{\frac{4(x-1)}{5}}{{e}^{2}}=\imath ovrlnx\]
Simplify  \(\frac{\frac{4(x-1)}{5}}{{e}^{2}}\)  to  \(\frac{4(x-1)}{5{e}^{2}}\).
\[\frac{4(x-1)}{5{e}^{2}}=\imath ovrlnx\]
Divide both sides by \(\imath \).
\[\frac{\frac{4(x-1)}{5{e}^{2}}}{\imath }=ovrlnx\]
Simplify  \(\frac{\frac{4(x-1)}{5{e}^{2}}}{\imath }\)  to  \(\frac{4(x-1)}{5{e}^{2}\imath }\).
\[\frac{4(x-1)}{5{e}^{2}\imath }=ovrlnx\]
Divide both sides by \(v\).
\[\frac{\frac{4(x-1)}{5{e}^{2}\imath }}{v}=orlnx\]
Simplify  \(\frac{\frac{4(x-1)}{5{e}^{2}\imath }}{v}\)  to  \(\frac{4(x-1)}{5{e}^{2}\imath v}\).
\[\frac{4(x-1)}{5{e}^{2}\imath v}=orlnx\]
Divide both sides by \(r\).
\[\frac{\frac{4(x-1)}{5{e}^{2}\imath v}}{r}=olnx\]
Simplify  \(\frac{\frac{4(x-1)}{5{e}^{2}\imath v}}{r}\)  to  \(\frac{4(x-1)}{5{e}^{2}\imath vr}\).
\[\frac{4(x-1)}{5{e}^{2}\imath vr}=olnx\]
Divide both sides by \(l\).
\[\frac{\frac{4(x-1)}{5{e}^{2}\imath vr}}{l}=onx\]
Simplify  \(\frac{\frac{4(x-1)}{5{e}^{2}\imath vr}}{l}\)  to  \(\frac{4(x-1)}{5{e}^{2}\imath vrl}\).
\[\frac{4(x-1)}{5{e}^{2}\imath vrl}=onx\]
Divide both sides by \(n\).
\[\frac{\frac{4(x-1)}{5{e}^{2}\imath vrl}}{n}=ox\]
Simplify  \(\frac{\frac{4(x-1)}{5{e}^{2}\imath vrl}}{n}\)  to  \(\frac{4(x-1)}{5{e}^{2}\imath vrln}\).
\[\frac{4(x-1)}{5{e}^{2}\imath vrln}=ox\]
Divide both sides by \(x\).
\[\frac{\frac{4(x-1)}{5{e}^{2}\imath vrln}}{x}=o\]
Simplify  \(\frac{\frac{4(x-1)}{5{e}^{2}\imath vrln}}{x}\)  to  \(\frac{4(x-1)}{5{e}^{2}\imath vrlnx}\).
\[\frac{4(x-1)}{5{e}^{2}\imath vrlnx}=o\]
Switch sides.
\[o=\frac{4(x-1)}{5{e}^{2}\imath vrlnx}\]