$$4x-7-(x+4)=3x+4-(2x-1$$
$x=8$
$$4x-7-x-4=3x+4-\left(2x-1\right)$$
$$3x-7-4=3x+4-\left(2x-1\right)$$
$$3x-11=3x+4-\left(2x-1\right)$$
$$3x-11=3x+4-2x-\left(-1\right)$$
$$3x-11=3x+4-2x+1$$
$$3x-11=x+4+1$$
$$3x-11=x+5$$
$$3x-11-x=5$$
$$2x-11=5$$
$$2x=5+11$$
$$2x=16$$
$$x=\frac{16}{2}$$
$$x=8$$
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