How to solve 4x-(5)/(3)=9

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4x-(5)/(3)=9 | Equatix

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$$4x- \frac{ 5 }{ 3 } =9$$

$x = \frac{8}{3} = 2\frac{2}{3} \approx 2.666666667$

Add $\frac{5}{3}$ to both sides.

$$4x=9+\frac{5}{3}$$

Convert $9$ to fraction $\frac{27}{3}$.

$$4x=\frac{27}{3}+\frac{5}{3}$$

Since $\frac{27}{3}$ and $\frac{5}{3}$ have the same denominator, add them by adding their numerators.

$$4x=\frac{27+5}{3}$$

Add $27$ and $5$ to get $32$.

$$4x=\frac{32}{3}$$

Divide both sides by $4$.

$$x=\frac{\frac{32}{3}}{4}$$

Express $\frac{\frac{32}{3}}{4}$ as a single fraction.

$$x=\frac{32}{3\times 4}$$

Multiply $3$ and $4$ to get $12$.

$$x=\frac{32}{12}$$

Reduce the fraction $\frac{32}{12}$ to lowest terms by extracting and canceling out $4$.

$$x=\frac{8}{3}$$