How to solve 4x+2 <= 3

Q: How to solve 4x+2 <= 3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4x+2 <= 3 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$4x+2 \leq 3$$

Solve for x

$x\leq \frac{1}{4}$

Solution Steps

Subtract $2$ from both sides.

$$4x\leq 3-2$$

Subtract $2$ from $3$ to get $1$.

$$4x\leq 1$$

Divide both sides by $4$. Since $4$ is positive, the inequality direction remains the same.

$$x\leq \frac{1}{4}$$

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