$$4x+2y+3a; 2x+3y+a$$
$\left(2x+3y+a\right)\left(4x+2y+3a\right)$
$$\left(2x+3y+a\right)\left(4x+2y+3a\right)$$
$$8x^{2}+10ax+16xy+6y^{2}+11ay+3a^{2}$$
Show Solution
Hide Solution
$4x+2y+3a,\ 2x+3y+a$
