How to solve 4x + 3 < 6x + 1

Q: How to solve 4x + 3 < 6x + 1

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4x + 3 < 6x + 1 | Equatix

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3(r+2s)=2t-4

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Question

$$4x+3<6x+1$$

Solve for x

$x>1$

Solution Steps

Subtract $6x$ from both sides.

$$4x+3-6x<1$$

Combine $4x$ and $-6x$ to get $-2x$.

$$-2x+3<1$$

Subtract $3$ from both sides.

$$-2x<1-3$$

Subtract $3$ from $1$ to get $-2$.

$$-2x<-2$$

Divide both sides by $-2$. Since $-2$ is negative, the inequality direction is changed.

$$x>\frac{-2}{-2}$$

Divide $-2$ by $-2$ to get $1$.

$$x>1$$

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Solve for x

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