How to solve 4x+5=5,-10y-4y=-7

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4x+5=5,-10y-4y=-7 | Equatix

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$$4x+5=5,-10y-4y=-7$$

$x=0$
$y=\frac{1}{2}=0.5$

Consider the first equation. Subtract $5$ from both sides.

$$4x=5-5$$

Subtract $5$ from $5$ to get $0$.

$$4x=0$$

Divide both sides by $4$. Zero divided by any non-zero number gives zero.

$$x=0$$

Consider the second equation. Combine $-10y$ and $-4y$ to get $-14y$.

$$-14y=-7$$

Divide both sides by $-14$.

$$y=\frac{-7}{-14}$$

Reduce the fraction $\frac{-7}{-14}$ to lowest terms by extracting and canceling out $-7$.

$$y=\frac{1}{2}$$

The system is now solved.

$$x=0$$ $$y=\frac{1}{2}$$