1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4x+x+3x | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$4x+x+3x$$

Evaluate

$8x$

Show Solution

Differentiate w.r.t. x

$8$

Steps Using Definition of a Derivative

Combine $4x$ and $x$ to get $5x$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(5x+3x)$$

Combine $5x$ and $3x$ to get $8x$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(8x)$$

The derivative of $ax^{n}$ is $nax^{n-1}$.

$$8x^{1-1}$$

Subtract $1$ from $1$.

$$8x^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$8\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$8$$

Show Solution

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Example

Question

Evaluate

Solution Steps

Differentiate w.r.t. x

Steps Using Definition of a Derivative