Question

$$4x^{2}-4x=9$$

Answer

x=(1+sqrt(10))/2,(1-sqrt(10))/2

Solution


Move all terms to one side.
\[4{x}^{2}-4x-9=0\]
Use the Quadratic Formula.
\[x=\frac{4+4\sqrt{10}}{8},\frac{4-4\sqrt{10}}{8}\]
Simplify solutions.
\[x=\frac{1+\sqrt{10}}{2},\frac{1-\sqrt{10}}{2}\]

Decimal Form: 2.081139, -1.081139