Question

$$4x^{2}+2\cdot=18+35x$$

Answer

x=(35+sqrt(1801))/8,(35-sqrt(1801))/8

Solution


Move all terms to one side.
\[4{x}^{2}+2\times -18-35x=0\]
Simplify  \(2\times -18\)  to  \(-36\).
\[4{x}^{2}-36-35x=0\]
Use the Quadratic Formula.
\[x=\frac{35+\sqrt{1801}}{8},\frac{35-\sqrt{1801}}{8}\]

Decimal Form: 9.679774, -0.929774