Simplify \(1\times hatc\) to \(hatc\).
\[4{x}^{2}+20=hatc+35x\]
Subtract \(35x\) from both sides.
\[4{x}^{2}+20-35x=hatc\]
Divide both sides by \(h\).
\[\frac{4{x}^{2}+20-35x}{h}=atc\]
Divide both sides by \(t\).
\[\frac{\frac{4{x}^{2}+20-35x}{h}}{t}=ac\]
Simplify \(\frac{\frac{4{x}^{2}+20-35x}{h}}{t}\) to \(\frac{4{x}^{2}+20-35x}{ht}\).
\[\frac{4{x}^{2}+20-35x}{ht}=ac\]
Divide both sides by \(c\).
\[\frac{\frac{4{x}^{2}+20-35x}{ht}}{c}=a\]
Simplify \(\frac{\frac{4{x}^{2}+20-35x}{ht}}{c}\) to \(\frac{4{x}^{2}+20-35x}{htc}\).
\[\frac{4{x}^{2}+20-35x}{htc}=a\]
Switch sides.
\[a=\frac{4{x}^{2}+20-35x}{htc}\]
a=(4*x^2+20-35*x)/(h*t*c)
