How to solve 4x ^ 2 + 6x + 9/4

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4x ^ 2 + 6x + 9/4 | Equatix

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$4x^{2}+6x+\frac{9}{4}$$

Factor

$\frac{\left(4x+3\right)^{2}}{4}$

Solution Steps

Factor out $\frac{1}{4}$.

$$\frac{16x^{2}+24x+9}{4}$$

Consider $16x^{2}+24x+9$. Use the perfect square formula, $a^{2}+2ab+b^{2}=\left(a+b\right)^{2}$, where $a=4x$ and $b=3$.

$$\left(4x+3\right)^{2}$$

Rewrite the complete factored expression.

$$\frac{\left(4x+3\right)^{2}}{4}$$

Show Solution

Evaluate

$\frac{\left(4x+3\right)^{2}}{4}$

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