How to solve 4x ^ 4 - 12 + 9

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4x ^ 4 - 12 + 9 | Equatix

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Question

$$4x^{4}-12+9$$

Differentiate w.r.t. x

$16x^{3}$

Steps Using Derivative Rule for Sum

Add $-12$ and $9$ to get $-3$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(4x^{4}-3)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$4\times 4x^{4-1}$$

Multiply $4$ times $4$.

$$16x^{4-1}$$

Subtract $1$ from $4$.

$$16x^{3}$$

Show Solution

Evaluate

$4x^{4}-3$

Show Solution

Example

Question

Differentiate w.r.t. x

Steps Using Derivative Rule for Sum

Evaluate

Solution Steps