How to solve 4xSQURE-5x+3=0

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 4xSQURE-5x+3=0 | Equatix

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Question

$$4xSQURE-5x+3=0$$

Solve for Q

$Q=\frac{3}{20SUxRe(x)}$
$xRe(x)\neq 0\text{ and }U\neq 0\text{ and }S\neq 0\text{ and }Re(x)\neq 0$

Steps for Solving Linear Equation

Subtract $3$ from both sides. Anything subtracted from zero gives its negation.

$$4xSQURe(-5x)=-3$$

The equation is in standard form.

$$\left(-20SUxRe(x)\right)Q=-3$$

Divide both sides by $-20UxSRe(x)$.

$$\frac{\left(-20SUxRe(x)\right)Q}{-20SUxRe(x)}=-\frac{3}{-20SUxRe(x)}$$

Dividing by $-20UxSRe(x)$ undoes the multiplication by $-20UxSRe(x)$.

$$Q=-\frac{3}{-20SUxRe(x)}$$

Divide $-3$ by $-20UxSRe(x)$.

$$Q=\frac{3}{20SUxRe(x)}$$

Show Solution

Solve for S

$S=\frac{3}{20QUxRe(x)}$
$xRe(x)\neq 0\text{ and }U\neq 0\text{ and }Q\neq 0\text{ and }Re(x)\neq 0$

Steps for Solving Linear Equation

Subtract $3$ from both sides. Anything subtracted from zero gives its negation.

$$4xSQURe(-5x)=-3$$

The equation is in standard form.

$$\left(-20QUxRe(x)\right)S=-3$$

Divide both sides by $-20UxRe(x)Q$.

$$\frac{\left(-20QUxRe(x)\right)S}{-20QUxRe(x)}=-\frac{3}{-20QUxRe(x)}$$

Dividing by $-20UxRe(x)Q$ undoes the multiplication by $-20UxRe(x)Q$.

$$S=-\frac{3}{-20QUxRe(x)}$$

Divide $-3$ by $-20UxRe(x)Q$.

$$S=\frac{3}{20QUxRe(x)}$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Example

Question

Solve for Q

Steps for Solving Linear Equation

Solve for S

Steps for Solving Linear Equation