$$4y-\frac{1}{3}x=-5$$
$x=12y+15$
$$-\frac{1}{3}x=-5-4y$$
$$-\frac{1}{3}x=-4y-5$$
$$\frac{-\frac{1}{3}x}{-\frac{1}{3}}=\frac{-4y-5}{-\frac{1}{3}}$$
$$x=\frac{-4y-5}{-\frac{1}{3}}$$
$$x=12y+15$$
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$y=\frac{x-15}{12}$
$$4y=-5+\frac{1}{3}x$$
$$4y=\frac{x}{3}-5$$
$$\frac{4y}{4}=\frac{\frac{x}{3}-5}{4}$$
$$y=\frac{\frac{x}{3}-5}{4}$$
$$y=\frac{x}{12}-\frac{5}{4}$$
