Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$5\cos^{-1}(-\frac{\sqrt{3}}{2}); -4\tan^{-1}(\sqrt{3})_{+}; 35in^{-1}(1)$$

Answer

5*(5*PI)/6;-(4*sqrt(3))/tan+;35*IM*1/n*1

Solution


Simplify  \(\cos^{-1}{(-\frac{\sqrt{3}}{2})}\)  to  \(\frac{5\pi }{6}\).
\[\begin{aligned}&5\times \frac{5\pi }{6}\\&-4{tan}^{-1}\sqrt{3}+\\&35\imath {n}^{-1}\times 1\end{aligned}\]
Use Negative Power Rule: \({x}^{-a}=\frac{1}{{x}^{a}}\).
\[\begin{aligned}&5\times \frac{5\pi }{6}\\&-4\times \frac{1}{tan}\sqrt{3}+\\&35\imath {n}^{-1}\times 1\end{aligned}\]
Use Negative Power Rule: \({x}^{-a}=\frac{1}{{x}^{a}}\).
\[\begin{aligned}&5\times \frac{5\pi }{6}\\&-4\times \frac{1}{tan}\sqrt{3}+\\&35\imath \times \frac{1}{n}\times 1\end{aligned}\]
Simplify  \(4\times \frac{1}{tan}\sqrt{3}\)  to  \(\frac{4\sqrt{3}}{tan}\).
\[\begin{aligned}&5\times \frac{5\pi }{6}\\&-\frac{4\sqrt{3}}{tan}+\\&35\imath \times \frac{1}{n}\times 1\end{aligned}\]
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