$$5 { x }^{ 2 } -5 \geq 0$$
$x\in (-\infty,-1]\cup [1,\infty)$
$$x^{2}\geq 1$$
$$x^{2}\geq 1^{2}$$
$$|x|\geq 1$$
$$x\leq -1\text{; }x\geq 1$$
Show Solution
Hide Solution
