$$5 { x }^{ 2 } +40+16$$
$10x$
$$\frac{\mathrm{d}}{\mathrm{d}x}(5x^{2}+56)$$
$$2\times 5x^{2-1}$$
$$10x^{2-1}$$
$$10x^{1}$$
$$10x$$
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$5x^{2}+56$
$$5x^{2}+56$$