Question

$$5 { x }^{ 2 } +8x+1=0$$

Answer

x=-(4-sqrt(11))/5,-(4+sqrt(11))/5

Solution


Use the Quadratic Formula.
\[x=\frac{-8+2\sqrt{11}}{10},\frac{-8-2\sqrt{11}}{10}\]
Simplify solutions.
\[x=-\frac{4-\sqrt{11}}{5},-\frac{4+\sqrt{11}}{5}\]

Decimal Form: -0.136675, -1.463325