Solve 5/36+-7/8+6/-72+-3/-12 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$5/36+-7/8+6/-72+-3/-12$$

Evaluate

$-\frac{41}{72}\approx -0.569444444$

Solution Steps

Fraction $\frac{-7}{8}$ can be rewritten as $-\frac{7}{8}$ by extracting the negative sign.

$$\frac{5}{36}-\frac{7}{8}+\frac{6}{-72}+\frac{-3}{-12}$$

Least common multiple of $36$ and $8$ is $72$. Convert $\frac{5}{36}$ and $\frac{7}{8}$ to fractions with denominator $72$.

$$\frac{10}{72}-\frac{63}{72}+\frac{6}{-72}+\frac{-3}{-12}$$

Since $\frac{10}{72}$ and $\frac{63}{72}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{10-63}{72}+\frac{6}{-72}+\frac{-3}{-12}$$

Subtract $63$ from $10$ to get $-53$.

$$-\frac{53}{72}+\frac{6}{-72}+\frac{-3}{-12}$$

Reduce the fraction $\frac{6}{-72}$ to lowest terms by extracting and canceling out $6$.

$$-\frac{53}{72}-\frac{1}{12}+\frac{-3}{-12}$$

Least common multiple of $72$ and $12$ is $72$. Convert $-\frac{53}{72}$ and $\frac{1}{12}$ to fractions with denominator $72$.

$$-\frac{53}{72}-\frac{6}{72}+\frac{-3}{-12}$$

Since $-\frac{53}{72}$ and $\frac{6}{72}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{-53-6}{72}+\frac{-3}{-12}$$

Subtract $6$ from $-53$ to get $-59$.

$$-\frac{59}{72}+\frac{-3}{-12}$$

Reduce the fraction $\frac{-3}{-12}$ to lowest terms by extracting and canceling out $-3$.

$$-\frac{59}{72}+\frac{1}{4}$$

Least common multiple of $72$ and $4$ is $72$. Convert $-\frac{59}{72}$ and $\frac{1}{4}$ to fractions with denominator $72$.

$$-\frac{59}{72}+\frac{18}{72}$$

Since $-\frac{59}{72}$ and $\frac{18}{72}$ have the same denominator, add them by adding their numerators.

$$\frac{-59+18}{72}$$

Add $-59$ and $18$ to get $-41$.

$$-\frac{41}{72}$$

Factor

$-\frac{41}{72} = -0.5694444444444444$