1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 5/5-2/4 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$5/5-2/4$$

Evaluate

$\frac{1}{2}=0.5$

Solution Steps

Divide $5$ by $5$ to get $1$.

$$1-\frac{2}{4}$$

Reduce the fraction $\frac{2}{4}$ to lowest terms by extracting and canceling out $2$.

$$1-\frac{1}{2}$$

Convert $1$ to fraction $\frac{2}{2}$.

$$\frac{2}{2}-\frac{1}{2}$$

Since $\frac{2}{2}$ and $\frac{1}{2}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{2-1}{2}$$

Subtract $1$ from $2$ to get $1$.

$$\frac{1}{2}$$

Show Solution

Factor

$\frac{1}{2} = 0.5$

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