$$5/(3-4+7)(24-5)+5$$
$\frac{125}{6}\approx 20.833333333$
$$\frac{5}{-1+7}\left(24-5\right)+5$$
$$\frac{5}{6}\left(24-5\right)+5$$
$$\frac{5}{6}\times 19+5$$
$$\frac{5\times 19}{6}+5$$
$$\frac{95}{6}+5$$
$$\frac{95}{6}+\frac{30}{6}$$
$$\frac{95+30}{6}$$
$$\frac{125}{6}$$
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$\frac{5 ^ {3}}{2 \cdot 3} = 20\frac{5}{6} = 20.833333333333332$
