Solve 5 - 10x - 3 - 5 + 20/- 2 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$5-10x-3-5+20\div-2$$

Evaluate

$-10x-13$

Solution Steps

Subtract $3$ from $5$ to get $2$.

$$2-10x-5+\frac{20}{-2}$$

Subtract $5$ from $2$ to get $-3$.

$$-3-10x+\frac{20}{-2}$$

Divide $20$ by $-2$ to get $-10$.

$$-3-10x-10$$

Subtract $10$ from $-3$ to get $-13$.

$$-13-10x$$

Differentiate w.r.t. x

$-10$

Steps Using Derivative Rule for Sum

Subtract $3$ from $5$ to get $2$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2-10x-5+\frac{20}{-2})$$

Subtract $5$ from $2$ to get $-3$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-3-10x+\frac{20}{-2})$$

Divide $20$ by $-2$ to get $-10$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-3-10x-10)$$

Subtract $10$ from $-3$ to get $-13$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-13-10x)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$-10x^{1-1}$$

Subtract $1$ from $1$.

$$-10x^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$-10$$