1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 5-2/5 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$5-2/5$$

Evaluate

$\frac{23}{5}=4.6$

Solution Steps

Convert $5$ to fraction $\frac{25}{5}$.

$$\frac{25}{5}-\frac{2}{5}$$

Since $\frac{25}{5}$ and $\frac{2}{5}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{25-2}{5}$$

Subtract $2$ from $25$ to get $23$.

$$\frac{23}{5}$$

Show Solution

Factor

$\frac{23}{5} = 4\frac{3}{5} = 4.6$

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