How to solve 5-2x < 20+3x

Q: How to solve 5-2x < 20+3x

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 5-2x < 20+3x | Equatix

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Question

$$5-2x < 20+3x$$

Solve for x

$x>-3$

Solution Steps

Subtract $3x$ from both sides.

$$5-2x-3x<20$$

Combine $-2x$ and $-3x$ to get $-5x$.

$$5-5x<20$$

Subtract $5$ from both sides.

$$-5x<20-5$$

Subtract $5$ from $20$ to get $15$.

$$-5x<15$$

Divide both sides by $-5$. Since $-5$ is negative, the inequality direction is changed.

$$x>\frac{15}{-5}$$

Divide $15$ by $-5$ to get $-3$.

$$x>-3$$

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