How to solve 5-3/5=2/5y-2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 5-3/5=2/5y-2 | Equatix

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Question

$$5-3/5=2/5y-2$$

Solve for y

$y=16$

Steps for Solving Linear Equation

Convert $5$ to fraction $\frac{25}{5}$.

$$\frac{25}{5}-\frac{3}{5}=\frac{2}{5}y-2$$

Since $\frac{25}{5}$ and $\frac{3}{5}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{25-3}{5}=\frac{2}{5}y-2$$

Subtract $3$ from $25$ to get $22$.

$$\frac{22}{5}=\frac{2}{5}y-2$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{2}{5}y-2=\frac{22}{5}$$

Add $2$ to both sides.

$$\frac{2}{5}y=\frac{22}{5}+2$$

Convert $2$ to fraction $\frac{10}{5}$.

$$\frac{2}{5}y=\frac{22}{5}+\frac{10}{5}$$

Since $\frac{22}{5}$ and $\frac{10}{5}$ have the same denominator, add them by adding their numerators.

$$\frac{2}{5}y=\frac{22+10}{5}$$

Add $22$ and $10$ to get $32$.

$$\frac{2}{5}y=\frac{32}{5}$$

Multiply both sides by $\frac{5}{2}$, the reciprocal of $\frac{2}{5}$.

$$y=\frac{32}{5}\times \frac{5}{2}$$

Multiply $\frac{32}{5}$ times $\frac{5}{2}$ by multiplying numerator times numerator and denominator times denominator.

$$y=\frac{32\times 5}{5\times 2}$$

Cancel out $5$ in both numerator and denominator.

$$y=\frac{32}{2}$$

Divide $32$ by $2$ to get $16$.

$$y=16$$

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