Question

$$5-3 \times [2 \times (4-1)-3 \times (-1-5)- \frac{ 8 }{ 4-2] }$$

Answer

23-9*[2-8/(4-2])

Solution


Simplify  \(4-1\)  to  \(3\).
5-3*\(2\times 3-3\times (-1-5)-8/\))
Simplify  \(-1-5\)  to  \(-6\).
5-3*\(2\times 3-3\times -6-8/\))
5-9*\(2-3\times -6-8/\))
Simplify  \(3\times -6\)  to  \(-18\).
5-9*\(2-(-18)-8/\))
Remove parentheses.
5-9*\(2+18-8/\))
Simplify.
23-9*\(2-8/\))