$$5-(\frac{8}{11}-3\frac{3}{11})$$
$\frac{83}{11}\approx 7.545454545$
$$5-\left(\frac{8}{11}-\frac{33+3}{11}\right)$$
$$5-\left(\frac{8}{11}-\frac{36}{11}\right)$$
$$5-\frac{8-36}{11}$$
$$5-\left(-\frac{28}{11}\right)$$
$$5+\frac{28}{11}$$
$$\frac{55}{11}+\frac{28}{11}$$
$$\frac{55+28}{11}$$
$$\frac{83}{11}$$
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$\frac{83}{11} = 7\frac{6}{11} = 7.545454545454546$
