How to solve 5-(-7)+3-(-4)+2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 5-(-7)+3-(-4)+2 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$5-(-7)+3-(-4)+2$$

Evaluate

$21$

Solution Steps

The opposite of $-7$ is $7$.

$$5+7+3-\left(-4\right)+2$$

Add $5$ and $7$ to get $12$.

$$12+3-\left(-4\right)+2$$

Add $12$ and $3$ to get $15$.

$$15-\left(-4\right)+2$$

The opposite of $-4$ is $4$.

$$15+4+2$$

Add $15$ and $4$ to get $19$.

$$19+2$$

Add $19$ and $2$ to get $21$.

$$21$$

Show Solution

Factor

$3\times 7$

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