Solve for \(T\) in \(5-T=3\).
Solve for \(T\).
\[5-T=3\]
Subtract \(5\) from both sides.
\[-T=3-5\]
Simplify \(3-5\) to \(-2\).
\[-T=-2\]
Multiply both sides by \(-1\).
\[T=2\]
\[T=2\]
Substitute \(T=2\) into \(\frac{5}{3}+\frac{T}{2}=6\).
Start with the original equation.
\[\frac{5}{3}+\frac{T}{2}=6\]
Let \(T=2\).
\[\frac{5}{3}+\frac{2}{2}=6\]
Simplify.
\[\frac{8}{3}=6\]
\[\frac{8}{3}=6\]
Since \(\frac{8}{3}=6\) is not true, this is an inconsistent system.