How to solve 5(1+2y)=(y-3)3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 5(1+2y)=(y-3)3 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$5(1+2y)=(y-3)3$$

Solve for y

$y=-2$

Steps for Solving Linear Equation

Use the distributive property to multiply $5$ by $1+2y$.

$$5+10y=\left(y-3\right)\times 3$$

Use the distributive property to multiply $y-3$ by $3$.

$$5+10y=3y-9$$

Subtract $3y$ from both sides.

$$5+10y-3y=-9$$

Combine $10y$ and $-3y$ to get $7y$.

$$5+7y=-9$$

Subtract $5$ from both sides.

$$7y=-9-5$$

Subtract $5$ from $-9$ to get $-14$.

$$7y=-14$$

Divide both sides by $7$.

$$y=\frac{-14}{7}$$

Divide $-14$ by $7$ to get $-2$.

$$y=-2$$

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Question

Solve for y

Steps for Solving Linear Equation