Solve 5(2x-4)+3(6x-1)=25(x+1) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$5(2x-4)+3(6x-1)=25(x+1)$$

Solve for x

$x=16$

Steps for Solving Linear Equation

Use the distributive property to multiply $5$ by $2x-4$.

$$10x-20+3\left(6x-1\right)=25\left(x+1\right)$$

Use the distributive property to multiply $3$ by $6x-1$.

$$10x-20+18x-3=25\left(x+1\right)$$

Combine $10x$ and $18x$ to get $28x$.

$$28x-20-3=25\left(x+1\right)$$

Subtract $3$ from $-20$ to get $-23$.

$$28x-23=25\left(x+1\right)$$

Use the distributive property to multiply $25$ by $x+1$.

$$28x-23=25x+25$$

Subtract $25x$ from both sides.

$$28x-23-25x=25$$

Combine $28x$ and $-25x$ to get $3x$.

$$3x-23=25$$

Add $23$ to both sides.

$$3x=25+23$$

Add $25$ and $23$ to get $48$.

$$3x=48$$

Divide both sides by $3$.

$$x=\frac{48}{3}$$

Divide $48$ by $3$ to get $16$.

$$x=16$$