How to solve 5(2z-2)=6(3z+3)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 5(2z-2)=6(3z+3) | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$5(2z-2)=6(3z+3)$$

Solve for z

$z = -\frac{7}{2} = -3\frac{1}{2} = -3.5$

Steps for Solving Linear Equation

Use the distributive property to multiply $5$ by $2z-2$.

$$10z-10=6\left(3z+3\right)$$

Use the distributive property to multiply $6$ by $3z+3$.

$$10z-10=18z+18$$

Subtract $18z$ from both sides.

$$10z-10-18z=18$$

Combine $10z$ and $-18z$ to get $-8z$.

$$-8z-10=18$$

Add $10$ to both sides.

$$-8z=18+10$$

Add $18$ and $10$ to get $28$.

$$-8z=28$$

Divide both sides by $-8$.

$$z=\frac{28}{-8}$$

Reduce the fraction $\frac{28}{-8}$ to lowest terms by extracting and canceling out $4$.

$$z=-\frac{7}{2}$$

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Solve for z

Steps for Solving Linear Equation